(x^2+7x+12)/(x+3)

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Solution for (x^2+7x+12)/(x+3) equation: 


D( x )

x+3 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:+oo)

(x^2+7*x+12)/(x+3) = 0

x^2+7*x+12 = 0

x^2+7*x+12 = 0

DELTA = 7^2-(1*4*12)

DELTA = 1

DELTA > 0

x = (1^(1/2)-7)/(1*2) or x = (-1^(1/2)-7)/(1*2)

x = -3 or x = -4

(x+4)*(x+3) = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x = -4

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